Solve 63y^2z^3/-7yz^2=

$$\frac { 63 y ^ { 2 } z ^ { 3 } } { - 7 y z ^ { 2 } } =$$

Evaluate

$$-9yz$$

Steps Using Quotient of Powers Property

Use the rules of exponents to simplify the expression.

$$\frac{63^{1}y^{2}z^{3}}{\left(-7\right)^{1}y^{1}z^{2}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$\frac{63^{1}}{\left(-7\right)^{1}}y^{2-1}z^{3-2}$$

Subtract 1 from 2.

$$\frac{63^{1}}{\left(-7\right)^{1}}y^{1}z^{3-2}$$

Subtract 2 from 3.

$$\frac{63^{1}}{\left(-7\right)^{1}}yz^{1}$$

Divide 63 by -7.

$$-9yz$$

Differentiate w.r.t. z

$$-9y$$