Solve 610/7+21/3=

$$\frac { 610 } { 7 } + 2 \frac { 1 } { 3 } =$$

Evaluate

$$\frac{1879}{21}\approx 89.476190476$$

Solution Steps

Multiply 2 and 3 to get 6.

$$\frac{610}{7}+\frac{6+1}{3}$$

Add 6 and 1 to get 7.

$$\frac{610}{7}+\frac{7}{3}$$

Least common multiple of 7 and 3 is 21. Convert \frac{610}{7} and \frac{7}{3} to fractions with denominator 21.

$$\frac{1830}{21}+\frac{49}{21}$$

Since \frac{1830}{21} and \frac{49}{21} have the same denominator, add them by adding their numerators.

$$\frac{1830+49}{21}$$

Add 1830 and 49 to get 1879.

$$\frac{1879}{21}$$

Factor

$$\frac{1879}{3 \cdot 7} = 89\frac{10}{21} = 89.47619047619048$$