Solve 60-1/7*4+60-2/7*3=25/6

$$\frac { 60 - 1 } { 7 \times 4 } + \frac { 60 - 2 } { 7 \times 3 } = \frac { 25 } { 6 }$$

Verify

Solution Steps

Subtract 1 from 60 to get 59.

$$\frac{59}{7\times 4}+\frac{60-2}{7\times 3}=\frac{25}{6}$$

Multiply 7 and 4 to get 28.

$$\frac{59}{28}+\frac{60-2}{7\times 3}=\frac{25}{6}$$

Subtract 2 from 60 to get 58.

$$\frac{59}{28}+\frac{58}{7\times 3}=\frac{25}{6}$$

Multiply 7 and 3 to get 21.

$$\frac{59}{28}+\frac{58}{21}=\frac{25}{6}$$

Least common multiple of 28 and 21 is 84. Convert \frac{59}{28} and \frac{58}{21} to fractions with denominator 84.

$$\frac{177}{84}+\frac{232}{84}=\frac{25}{6}$$

Since \frac{177}{84} and \frac{232}{84} have the same denominator, add them by adding their numerators.

$$\frac{177+232}{84}=\frac{25}{6}$$

Add 177 and 232 to get 409.

$$\frac{409}{84}=\frac{25}{6}$$

Least common multiple of 84 and 6 is 84. Convert \frac{409}{84} and \frac{25}{6} to fractions with denominator 84.

$$\frac{409}{84}=\frac{350}{84}$$

Compare \frac{409}{84} and \frac{350}{84}.

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