Solve 6,0*10^3*1,2*10^-3/4,8*10^-6*2,4*10^8

$$\frac { 6,0 \times 10 ^ { 3 } \cdot 1,2 \times 10 ^ { - 3 } } { 4,8 \times 10 ^ { - 6 } \cdot 2,4 \times 10 ^ { 8 } }$$

Evaluate

$$0,00625$$

Solution Steps

Multiply 10^{3} and 10^{-3} to get 1.

$$\frac{6\times 1,2}{4,8\times 10^{-6}\times 2,4\times 10^{8}}$$

To multiply powers of the same base, add their exponents. Add -6 and 8 to get 2.

$$\frac{6\times 1,2}{4,8\times 10^{2}\times 2,4}$$

Multiply 6 and 1,2 to get 7,2.

$$\frac{7,2}{4,8\times 10^{2}\times 2,4}$$

Calculate 10 to the power of 2 and get 100.

$$\frac{7,2}{4,8\times 100\times 2,4}$$

Multiply 4,8 and 100 to get 480.

$$\frac{7,2}{480\times 2,4}$$

Multiply 480 and 2,4 to get 1152.

$$\frac{7,2}{1152}$$

Expand \frac{7,2}{1152} by multiplying both numerator and the denominator by 10.

$$\frac{72}{11520}$$

Reduce the fraction \frac{72}{11520} to lowest terms by extracting and canceling out 72.

$$\frac{1}{160}$$

Factor

$$\frac{1}{5 \cdot 2 ^ {5}} = 0.00625$$