Solve for x
x=\frac{1}{5}=0.2
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Linear Equation
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\frac { 6 x - 1 } { 2 x + 1 } = \frac { 3 x - 1 } { x - 3 }
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\left(x-3\right)\left(6x-1\right)=\left(2x+1\right)\left(3x-1\right)
Variable x cannot be equal to any of the values -\frac{1}{2},3 since division by zero is not defined. Multiply both sides of the equation by \left(x-3\right)\left(2x+1\right), the least common multiple of 2x+1,x-3.
6x^{2}-19x+3=\left(2x+1\right)\left(3x-1\right)
Use the distributive property to multiply x-3 by 6x-1 and combine like terms.
6x^{2}-19x+3=6x^{2}+x-1
Use the distributive property to multiply 2x+1 by 3x-1 and combine like terms.
6x^{2}-19x+3-6x^{2}=x-1
Subtract 6x^{2} from both sides.
-19x+3=x-1
Combine 6x^{2} and -6x^{2} to get 0.
-19x+3-x=-1
Subtract x from both sides.
-20x+3=-1
Combine -19x and -x to get -20x.
-20x=-1-3
Subtract 3 from both sides.
-20x=-4
Subtract 3 from -1 to get -4.
x=\frac{-4}{-20}
Divide both sides by -20.
x=\frac{1}{5}
Reduce the fraction \frac{-4}{-20} to lowest terms by extracting and canceling out -4.
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