Solve 6x+3/x=3(2x+1)/x

$$\frac { 6 x + 3 } { x } = \frac { 3 ( 2 x + 1 ) } { x }$$

Solve for x

$$x\neq 0$$

Solution Steps

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.

$$6x+3=3\left(2x+1\right)$$

Use the distributive property to multiply 3 by 2x+1.

$$6x+3=6x+3$$

Subtract 6x from both sides.

$$6x+3-6x=3$$

Combine 6x and -6x to get 0.

$$3=3$$

Compare 3 and 3.

$$\text{true}$$

This is true for any x.

$$x\in \mathrm{R}$$

Variable x cannot be equal to 0.

$$x\in \mathrm{R}\setminus 0$$