Solve 6pq^2/7rdiv2p^2q^2/21r^2

$$\frac { 6 p q ^ { 2 } } { 7 r } \div \frac { 2 p ^ { 2 } q ^ { 2 } } { 21 r ^ { 2 } }$$

Evaluate

$$\frac{9r}{p}$$

Solution Steps

Divide \frac{6pq^{2}}{7r} by \frac{2p^{2}q^{2}}{21r^{2}} by multiplying \frac{6pq^{2}}{7r} by the reciprocal of \frac{2p^{2}q^{2}}{21r^{2}}.

$$\frac{6pq^{2}\times 21r^{2}}{7r\times 2p^{2}q^{2}}$$

Cancel out 2\times 7prq^{2} in both numerator and denominator.

$$\frac{3\times 3r}{p}$$

Multiply 3 and 3 to get 9.

$$\frac{9r}{p}$$

Differentiate w.r.t. p

$$-\frac{9r}{p^{2}}$$