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6-\sqrt{2}+\left(x+5\right)\left(-3\right)=0
Variable x cannot be equal to -5 since division by zero is not defined. Multiply both sides of the equation by x+5.
6-\sqrt{2}-3x-15=0
Use the distributive property to multiply x+5 by -3.
-9-\sqrt{2}-3x=0
Subtract 15 from 6 to get -9.
-\sqrt{2}-3x=9
Add 9 to both sides. Anything plus zero gives itself.
-3x=9+\sqrt{2}
Add \sqrt{2} to both sides.
-3x=\sqrt{2}+9
The equation is in standard form.
\frac{-3x}{-3}=\frac{\sqrt{2}+9}{-3}
Divide both sides by -3.
x=\frac{\sqrt{2}+9}{-3}
Dividing by -3 undoes the multiplication by -3.
x=-\frac{\sqrt{2}}{3}-3
Divide 9+\sqrt{2} by -3.