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5\times 6=x\left(2x+4\right)
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 5x, the least common multiple of x,5.
30=x\left(2x+4\right)
Multiply 5 and 6 to get 30.
30=2x^{2}+4x
Use the distributive property to multiply x by 2x+4.
2x^{2}+4x=30
Swap sides so that all variable terms are on the left hand side.
2x^{2}+4x-30=0
Subtract 30 from both sides.
x=\frac{-4±\sqrt{4^{2}-4\times 2\left(-30\right)}}{2\times 2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 2 for a, 4 for b, and -30 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-4±\sqrt{16-4\times 2\left(-30\right)}}{2\times 2}
Square 4.
x=\frac{-4±\sqrt{16-8\left(-30\right)}}{2\times 2}
Multiply -4 times 2.
x=\frac{-4±\sqrt{16+240}}{2\times 2}
Multiply -8 times -30.
x=\frac{-4±\sqrt{256}}{2\times 2}
Add 16 to 240.
x=\frac{-4±16}{2\times 2}
Take the square root of 256.
x=\frac{-4±16}{4}
Multiply 2 times 2.
x=\frac{12}{4}
Now solve the equation x=\frac{-4±16}{4} when ± is plus. Add -4 to 16.
x=3
Divide 12 by 4.
x=-\frac{20}{4}
Now solve the equation x=\frac{-4±16}{4} when ± is minus. Subtract 16 from -4.
x=-5
Divide -20 by 4.
x=3 x=-5
The equation is now solved.
5\times 6=x\left(2x+4\right)
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 5x, the least common multiple of x,5.
30=x\left(2x+4\right)
Multiply 5 and 6 to get 30.
30=2x^{2}+4x
Use the distributive property to multiply x by 2x+4.
2x^{2}+4x=30
Swap sides so that all variable terms are on the left hand side.
\frac{2x^{2}+4x}{2}=\frac{30}{2}
Divide both sides by 2.
x^{2}+\frac{4}{2}x=\frac{30}{2}
Dividing by 2 undoes the multiplication by 2.
x^{2}+2x=\frac{30}{2}
Divide 4 by 2.
x^{2}+2x=15
Divide 30 by 2.
x^{2}+2x+1^{2}=15+1^{2}
Divide 2, the coefficient of the x term, by 2 to get 1. Then add the square of 1 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+2x+1=15+1
Square 1.
x^{2}+2x+1=16
Add 15 to 1.
\left(x+1\right)^{2}=16
Factor x^{2}+2x+1. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+1\right)^{2}}=\sqrt{16}
Take the square root of both sides of the equation.
x+1=4 x+1=-4
Simplify.
x=3 x=-5
Subtract 1 from both sides of the equation.