Solve 6/x+8y=4

$$\frac { 6 } { x } + 8 y = 4$$

Solve for x

$$x=-\frac{3}{2\left(2y-1\right)}$$

$$y\neq \frac{1}{2}$$

Steps for Solving Linear Equation

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.

$$6+8yx=4x$$

Subtract 4x from both sides.

$$6+8yx-4x=0$$

Subtract 6 from both sides. Anything subtracted from zero gives its negation.

$$8yx-4x=-6$$

Combine all terms containing x.

$$\left(8y-4\right)x=-6$$

Divide both sides by 8y-4.

$$\frac{\left(8y-4\right)x}{8y-4}=-\frac{6}{8y-4}$$

Dividing by 8y-4 undoes the multiplication by 8y-4.

$$x=-\frac{6}{8y-4}$$

Divide -6 by 8y-4.

$$x=-\frac{3}{2\left(2y-1\right)}$$

Variable x cannot be equal to 0.

$$x=-\frac{3}{2\left(2y-1\right)}\text{, }x\neq 0$$

Solve for y

$$y=\frac{1}{2}-\frac{3}{4x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by x.

$$6+8yx=4x$$

Subtract 6 from both sides.

$$8yx=4x-6$$

The equation is in standard form.

$$8xy=4x-6$$

Divide both sides by 8x.

$$\frac{8xy}{8x}=\frac{4x-6}{8x}$$

Dividing by 8x undoes the multiplication by 8x.

$$y=\frac{4x-6}{8x}$$

Divide 4x-6 by 8x.

$$y=\frac{1}{2}-\frac{3}{4x}$$