Solve 6/9*(3/5+1/5)=

$$\frac { 6 } { 9 } \cdot ( \frac { 3 } { 5 } + \frac { 1 } { 5 } ) =$$

Evaluate

$$\frac{8}{15}\approx 0.533333333$$

Solution Steps

Reduce the fraction \frac{6}{9} to lowest terms by extracting and canceling out 3.

$$\frac{2}{3}\left(\frac{3}{5}+\frac{1}{5}\right)$$

Since \frac{3}{5} and \frac{1}{5} have the same denominator, add them by adding their numerators.

$$\frac{2}{3}\times \frac{3+1}{5}$$

Add 3 and 1 to get 4.

$$\frac{2}{3}\times \frac{4}{5}$$

Multiply \frac{2}{3} times \frac{4}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{2\times 4}{3\times 5}$$

Do the multiplications in the fraction \frac{2\times 4}{3\times 5}.

$$\frac{8}{15}$$

Factor

$$\frac{2 ^ {3}}{3 \cdot 5} = 0.5333333333333333$$