Solve 6/9+4^2/18-3/6+12/3=

$$\frac { 6 } { 9 } + \frac { 4 ^ { 2 } } { 18 } - \frac { 3 } { 6 } + \frac { 12 } { 3 } =$$

Evaluate

$$\frac{91}{18}\approx 5.055555556$$

Solution Steps

Reduce the fraction \frac{6}{9} to lowest terms by extracting and canceling out 3.

$$\frac{2}{3}+\frac{4^{2}}{18}-\frac{3}{6}+\frac{12}{3}$$

Calculate 4 to the power of 2 and get 16.

$$\frac{2}{3}+\frac{16}{18}-\frac{3}{6}+\frac{12}{3}$$

Reduce the fraction \frac{16}{18} to lowest terms by extracting and canceling out 2.

$$\frac{2}{3}+\frac{8}{9}-\frac{3}{6}+\frac{12}{3}$$

Least common multiple of 3 and 9 is 9. Convert \frac{2}{3} and \frac{8}{9} to fractions with denominator 9.

$$\frac{6}{9}+\frac{8}{9}-\frac{3}{6}+\frac{12}{3}$$

Since \frac{6}{9} and \frac{8}{9} have the same denominator, add them by adding their numerators.

$$\frac{6+8}{9}-\frac{3}{6}+\frac{12}{3}$$

Add 6 and 8 to get 14.

$$\frac{14}{9}-\frac{3}{6}+\frac{12}{3}$$

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$\frac{14}{9}-\frac{1}{2}+\frac{12}{3}$$

Least common multiple of 9 and 2 is 18. Convert \frac{14}{9} and \frac{1}{2} to fractions with denominator 18.

$$\frac{28}{18}-\frac{9}{18}+\frac{12}{3}$$

Since \frac{28}{18} and \frac{9}{18} have the same denominator, subtract them by subtracting their numerators.

$$\frac{28-9}{18}+\frac{12}{3}$$

Subtract 9 from 28 to get 19.

$$\frac{19}{18}+\frac{12}{3}$$

Divide 12 by 3 to get 4.

$$\frac{19}{18}+4$$

Convert 4 to fraction \frac{72}{18}.

$$\frac{19}{18}+\frac{72}{18}$$

Since \frac{19}{18} and \frac{72}{18} have the same denominator, add them by adding their numerators.

$$\frac{19+72}{18}$$

Add 19 and 72 to get 91.

$$\frac{91}{18}$$

Factor

$$\frac{7 \cdot 13}{2 \cdot 3 ^ {2}} = 5\frac{1}{18} = 5.055555555555555$$