Solve 6/84+8/24*2^2=

$$\frac { 6 } { 84 } + \frac { 8 } { 24 } \cdot 2 ^ { 2 } =$$

Evaluate

$$\frac{59}{42}\approx 1.404761905$$

Solution Steps

Reduce the fraction \frac{6}{84} to lowest terms by extracting and canceling out 6.

$$\frac{1}{14}+\frac{8}{24}\times 2^{2}$$

Reduce the fraction \frac{8}{24} to lowest terms by extracting and canceling out 8.

$$\frac{1}{14}+\frac{1}{3}\times 2^{2}$$

Calculate 2 to the power of 2 and get 4.

$$\frac{1}{14}+\frac{1}{3}\times 4$$

Multiply \frac{1}{3} and 4 to get \frac{4}{3}.

$$\frac{1}{14}+\frac{4}{3}$$

Least common multiple of 14 and 3 is 42. Convert \frac{1}{14} and \frac{4}{3} to fractions with denominator 42.

$$\frac{3}{42}+\frac{56}{42}$$

Since \frac{3}{42} and \frac{56}{42} have the same denominator, add them by adding their numerators.

$$\frac{3+56}{42}$$

Add 3 and 56 to get 59.

$$\frac{59}{42}$$

Factor

$$\frac{59}{2 \cdot 3 \cdot 7} = 1\frac{17}{42} = 1.4047619047619047$$