Solve 6/8+8=(6+8)/8=1/8

$$\frac { 6 } { 8 } + 8 = \frac { ( 6 + 8 ) } { 8 } = \frac { 1 } { 8 }$$

Verify

Solution Steps

Reduce the fraction \frac{6}{8} to lowest terms by extracting and canceling out 2.

$$\frac{3}{4}+8=\frac{6+8}{8}\text{ and }\frac{6+8}{8}=\frac{1}{8}$$

Convert 8 to fraction \frac{32}{4}.

$$\frac{3}{4}+\frac{32}{4}=\frac{6+8}{8}\text{ and }\frac{6+8}{8}=\frac{1}{8}$$

Since \frac{3}{4} and \frac{32}{4} have the same denominator, add them by adding their numerators.

$$\frac{3+32}{4}=\frac{6+8}{8}\text{ and }\frac{6+8}{8}=\frac{1}{8}$$

Add 3 and 32 to get 35.

$$\frac{35}{4}=\frac{6+8}{8}\text{ and }\frac{6+8}{8}=\frac{1}{8}$$

Add 6 and 8 to get 14.

$$\frac{35}{4}=\frac{14}{8}\text{ and }\frac{6+8}{8}=\frac{1}{8}$$

Reduce the fraction \frac{14}{8} to lowest terms by extracting and canceling out 2.

$$\frac{35}{4}=\frac{7}{4}\text{ and }\frac{6+8}{8}=\frac{1}{8}$$

Compare \frac{35}{4} and \frac{7}{4}.

$$\text{false}\text{ and }\frac{6+8}{8}=\frac{1}{8}$$

Add 6 and 8 to get 14.

$$\text{false}\text{ and }\frac{14}{8}=\frac{1}{8}$$

Compare \frac{14}{8} and \frac{1}{8}.

$$\text{false}\text{ and }\text{false}$$

The conjunction of \text{false} and \text{false} is \text{false}.

$$\text{false}$$