Solve 6/5x+1/3>4/3

$$\frac { 6 } { 5 } x + \frac { 1 } { 3 } > \frac { 4 } { 3 }$$

Solve for x

$$x>\frac{5}{6}$$

Solution Steps

Subtract \frac{1}{3} from both sides.

$$\frac{6}{5}x>\frac{4}{3}-\frac{1}{3}$$

Since \frac{4}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{6}{5}x>\frac{4-1}{3}$$

Subtract 1 from 4 to get 3.

$$\frac{6}{5}x>\frac{3}{3}$$

Divide 3 by 3 to get 1.

$$\frac{6}{5}x>1$$

Multiply both sides by \frac{5}{6}, the reciprocal of \frac{6}{5}. Since \frac{6}{5} is positive, the inequality direction remains the same.

$$x>1\times \frac{5}{6}$$

Multiply 1 and \frac{5}{6} to get \frac{5}{6}.

$$x>\frac{5}{6}$$