Solve 6/4cj+5/3c^2=

$$\frac { 6 } { 4 c j } + \frac { 5 } { 3 c ^ { 2 } } =$$

Evaluate

$$\frac{3}{2cj}+\frac{5}{3c^{2}}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 4cj and 3c^{2} is 12jc^{2}. Multiply \frac{6}{4cj} times \frac{3c}{3c}. Multiply \frac{5}{3c^{2}} times \frac{4j}{4j}.

$$\frac{6\times 3c}{12jc^{2}}+\frac{5\times 4j}{12jc^{2}}$$

Since \frac{6\times 3c}{12jc^{2}} and \frac{5\times 4j}{12jc^{2}} have the same denominator, add them by adding their numerators.

$$\frac{6\times 3c+5\times 4j}{12jc^{2}}$$

Do the multiplications in 6\times 3c+5\times 4j.

$$\frac{18c+20j}{12jc^{2}}$$

Factor the expressions that are not already factored in \frac{18c+20j}{12jc^{2}}.

$$\frac{2\left(9c+10j\right)}{12jc^{2}}$$

Cancel out 2 in both numerator and denominator.

$$\frac{9c+10j}{6jc^{2}}$$

Factor

$$\frac{\frac{10j}{c}+9}{6cj}$$