Solve 6/4=8*8^-2/8^-3

$$\frac { 6 } { 4 } = \frac { 8 \times 8 ^ { - 2 } } { 8 ^ { - 3 } }$$

Verify

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and -2 to get -1.

$$\frac{6}{4}=\frac{8^{-1}}{8^{-3}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract -3 from -1 to get 2.

$$\frac{6}{4}=8^{2}$$

Reduce the fraction \frac{6}{4} to lowest terms by extracting and canceling out 2.

$$\frac{3}{2}=8^{2}$$

Calculate 8 to the power of 2 and get 64.

$$\frac{3}{2}=64$$

Convert 64 to fraction \frac{128}{2}.

$$\frac{3}{2}=\frac{128}{2}$$

Compare \frac{3}{2} and \frac{128}{2}.

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