Solve 6/3-2*[(1-2)^2-(2-3)^2/sqrt{64-3/17}]^2=

$$\frac { 6 } { 3 } - 2 \cdot [ \frac { ( 1 - 2 ) ^ { 2 } - ( 2 - 3 ) ^ { 2 } } { \sqrt { 64 } - \frac { 3 } { 17 } } ] ^ { 2 } =$$

Evaluate

$$2$$

Solution Steps

Divide 6 by 3 to get 2.

$$2-2\times \left(\frac{\left(1-2\right)^{2}-\left(2-3\right)^{2}}{\sqrt{64}-\frac{3}{17}}\right)^{2}$$

Subtract 2 from 1 to get -1.

$$2-2\times \left(\frac{\left(-1\right)^{2}-\left(2-3\right)^{2}}{\sqrt{64}-\frac{3}{17}}\right)^{2}$$

Calculate -1 to the power of 2 and get 1.

$$2-2\times \left(\frac{1-\left(2-3\right)^{2}}{\sqrt{64}-\frac{3}{17}}\right)^{2}$$

Subtract 3 from 2 to get -1.

$$2-2\times \left(\frac{1-\left(-1\right)^{2}}{\sqrt{64}-\frac{3}{17}}\right)^{2}$$

Calculate -1 to the power of 2 and get 1.

$$2-2\times \left(\frac{1-1}{\sqrt{64}-\frac{3}{17}}\right)^{2}$$

Subtract 1 from 1 to get 0.

$$2-2\times \left(\frac{0}{\sqrt{64}-\frac{3}{17}}\right)^{2}$$

Calculate the square root of 64 and get 8.

$$2-2\times \left(\frac{0}{8-\frac{3}{17}}\right)^{2}$$

Subtract \frac{3}{17} from 8 to get \frac{133}{17}.

$$2-2\times \left(\frac{0}{\frac{133}{17}}\right)^{2}$$

Zero divided by any non-zero number gives zero.

$$2-2\times 0^{2}$$

Calculate 0 to the power of 2 and get 0.

$$2-2\times 0$$

Multiply 2 and 0 to get 0.

$$2-0$$

Subtract 0 from 2 to get 2.

$$2$$

Factor

$$2$$