Solve 6/14+3/7=(1/3+1/6)

$$\frac { 6 } { 14 } + \frac { 3 } { 7 } = ( \frac { 1 } { 3 } + \frac { 1 } { 6 } )$$

Verify

Solution Steps

Reduce the fraction \frac{6}{14} to lowest terms by extracting and canceling out 2.

$$\frac{3}{7}+\frac{3}{7}=\frac{1}{3}+\frac{1}{6}$$

Since \frac{3}{7} and \frac{3}{7} have the same denominator, add them by adding their numerators.

$$\frac{3+3}{7}=\frac{1}{3}+\frac{1}{6}$$

Add 3 and 3 to get 6.

$$\frac{6}{7}=\frac{1}{3}+\frac{1}{6}$$

Least common multiple of 3 and 6 is 6. Convert \frac{1}{3} and \frac{1}{6} to fractions with denominator 6.

$$\frac{6}{7}=\frac{2}{6}+\frac{1}{6}$$

Since \frac{2}{6} and \frac{1}{6} have the same denominator, add them by adding their numerators.

$$\frac{6}{7}=\frac{2+1}{6}$$

Add 2 and 1 to get 3.

$$\frac{6}{7}=\frac{3}{6}$$

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$\frac{6}{7}=\frac{1}{2}$$

Least common multiple of 7 and 2 is 14. Convert \frac{6}{7} and \frac{1}{2} to fractions with denominator 14.

$$\frac{12}{14}=\frac{7}{14}$$

Compare \frac{12}{14} and \frac{7}{14}.

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