Solve 6/11-1+(1-15/22)-(3+1/4)=

$$\frac { 6 } { 11 } - 1 + ( 1 - \frac { 15 } { 22 } ) - ( 3 + \frac { 1 } { 4 } ) =$$

Evaluate

$$-\frac{149}{44}\approx -3.386363636$$

Solution Steps

Convert 1 to fraction \frac{11}{11}.

$$\frac{6}{11}-\frac{11}{11}+1-\frac{15}{22}-\left(3+\frac{1}{4}\right)$$

Since \frac{6}{11} and \frac{11}{11} have the same denominator, subtract them by subtracting their numerators.

$$\frac{6-11}{11}+1-\frac{15}{22}-\left(3+\frac{1}{4}\right)$$

Subtract 11 from 6 to get -5.

$$-\frac{5}{11}+1-\frac{15}{22}-\left(3+\frac{1}{4}\right)$$

Convert 1 to fraction \frac{11}{11}.

$$-\frac{5}{11}+\frac{11}{11}-\frac{15}{22}-\left(3+\frac{1}{4}\right)$$

Since -\frac{5}{11} and \frac{11}{11} have the same denominator, add them by adding their numerators.

$$\frac{-5+11}{11}-\frac{15}{22}-\left(3+\frac{1}{4}\right)$$

Add -5 and 11 to get 6.

$$\frac{6}{11}-\frac{15}{22}-\left(3+\frac{1}{4}\right)$$

Least common multiple of 11 and 22 is 22. Convert \frac{6}{11} and \frac{15}{22} to fractions with denominator 22.

$$\frac{12}{22}-\frac{15}{22}-\left(3+\frac{1}{4}\right)$$

Since \frac{12}{22} and \frac{15}{22} have the same denominator, subtract them by subtracting their numerators.

$$\frac{12-15}{22}-\left(3+\frac{1}{4}\right)$$

Subtract 15 from 12 to get -3.

$$-\frac{3}{22}-\left(3+\frac{1}{4}\right)$$

Convert 3 to fraction \frac{12}{4}.

$$-\frac{3}{22}-\left(\frac{12}{4}+\frac{1}{4}\right)$$

Since \frac{12}{4} and \frac{1}{4} have the same denominator, add them by adding their numerators.

$$-\frac{3}{22}-\frac{12+1}{4}$$

Add 12 and 1 to get 13.

$$-\frac{3}{22}-\frac{13}{4}$$

Least common multiple of 22 and 4 is 44. Convert -\frac{3}{22} and \frac{13}{4} to fractions with denominator 44.

$$-\frac{6}{44}-\frac{143}{44}$$

Since -\frac{6}{44} and \frac{143}{44} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-6-143}{44}$$

Subtract 143 from -6 to get -149.

$$-\frac{149}{44}$$

Factor

$$-\frac{149}{44} = -3\frac{17}{44} = -3.3863636363636362$$