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\frac{6\sqrt{3}}{\left(\sqrt{3}\right)^{2}}+\sqrt{3}
Rationalize the denominator of \frac{6}{\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
\frac{6\sqrt{3}}{3}+\sqrt{3}
The square of \sqrt{3} is 3.
2\sqrt{3}+\sqrt{3}
Divide 6\sqrt{3} by 3 to get 2\sqrt{3}.
3\sqrt{3}
Combine 2\sqrt{3} and \sqrt{3} to get 3\sqrt{3}.