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\frac{\left(6\sqrt{14}-4\sqrt{2}\right)\sqrt{2}}{2\left(\sqrt{2}\right)^{2}}
Rationalize the denominator of \frac{6\sqrt{14}-4\sqrt{2}}{2\sqrt{2}} by multiplying numerator and denominator by \sqrt{2}.
\frac{\left(6\sqrt{14}-4\sqrt{2}\right)\sqrt{2}}{2\times 2}
The square of \sqrt{2} is 2.
\frac{\left(6\sqrt{14}-4\sqrt{2}\right)\sqrt{2}}{4}
Multiply 2 and 2 to get 4.
\frac{6\sqrt{14}\sqrt{2}-4\left(\sqrt{2}\right)^{2}}{4}
Use the distributive property to multiply 6\sqrt{14}-4\sqrt{2} by \sqrt{2}.
\frac{6\sqrt{2}\sqrt{7}\sqrt{2}-4\left(\sqrt{2}\right)^{2}}{4}
Factor 14=2\times 7. Rewrite the square root of the product \sqrt{2\times 7} as the product of square roots \sqrt{2}\sqrt{7}.
\frac{6\times 2\sqrt{7}-4\left(\sqrt{2}\right)^{2}}{4}
Multiply \sqrt{2} and \sqrt{2} to get 2.
\frac{12\sqrt{7}-4\left(\sqrt{2}\right)^{2}}{4}
Multiply 6 and 2 to get 12.
\frac{12\sqrt{7}-4\times 2}{4}
The square of \sqrt{2} is 2.
\frac{12\sqrt{7}-8}{4}
Multiply -4 and 2 to get -8.
3\sqrt{7}-2
Divide each term of 12\sqrt{7}-8 by 4 to get 3\sqrt{7}-2.