Solve 61/2/-frac{1{4}+3/4}

$$\frac { 6 \frac { 1 } { 2 } } { - \frac { 1 } { 4 } + \frac { 3 } { 4 } }$$

Evaluate

$$13$$

Solution Steps

Multiply 6 and 2 to get 12.

$$\frac{\frac{12+1}{2}}{-\frac{1}{4}+\frac{3}{4}}$$

Add 12 and 1 to get 13.

$$\frac{\frac{13}{2}}{-\frac{1}{4}+\frac{3}{4}}$$

Since -\frac{1}{4} and \frac{3}{4} have the same denominator, add them by adding their numerators.

$$\frac{\frac{13}{2}}{\frac{-1+3}{4}}$$

Add -1 and 3 to get 2.

$$\frac{\frac{13}{2}}{\frac{2}{4}}$$

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$\frac{\frac{13}{2}}{\frac{1}{2}}$$

Divide \frac{13}{2} by \frac{1}{2} by multiplying \frac{13}{2} by the reciprocal of \frac{1}{2}.

$$\frac{13}{2}\times 2$$

Cancel out 2 and 2.

$$13$$

Factor

$$13$$