Solve 6^2-16^2/40*(4-2)

$$\frac { 6 ^ { 2 } - 16 ^ { 2 } } { 40 \times ( 4 - 2 ) }$$

Evaluate

$$-\frac{11}{4}=-2.75$$

Solution Steps

Calculate 6 to the power of 2 and get 36.

$$\frac{36-16^{2}}{40\left(4-2\right)}$$

Calculate 16 to the power of 2 and get 256.

$$\frac{36-256}{40\left(4-2\right)}$$

Subtract 256 from 36 to get -220.

$$\frac{-220}{40\left(4-2\right)}$$

Subtract 2 from 4 to get 2.

$$\frac{-220}{40\times 2}$$

Multiply 40 and 2 to get 80.

$$\frac{-220}{80}$$

Reduce the fraction \frac{-220}{80} to lowest terms by extracting and canceling out 20.

$$-\frac{11}{4}$$

Factor

$$-\frac{11}{4} = -2\frac{3}{4} = -2.75$$