Solve 6+|2-8|-3^2/3-18

$$\frac { 6 + | 2 - 8 | - 3 ^ { 2 } } { 3 - 18 }$$

Evaluate

$$-\frac{1}{5}=-0.2$$

Solution Steps

Subtract 8 from 2 to get -6.

$$\frac{6+|-6|-3^{2}}{3-18}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -6 is 6.

$$\frac{6+6-3^{2}}{3-18}$$

Add 6 and 6 to get 12.

$$\frac{12-3^{2}}{3-18}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{12-9}{3-18}$$

Subtract 9 from 12 to get 3.

$$\frac{3}{3-18}$$

Subtract 18 from 3 to get -15.

$$\frac{3}{-15}$$

Reduce the fraction \frac{3}{-15} to lowest terms by extracting and canceling out 3.

$$-\frac{1}{5}$$

Factor

$$-\frac{1}{5} = -0.2$$