Solve 50-32/212-32=x-(-50)/250-(-50)

$$\frac { 50 - 32 } { 212 - 32 } = \frac { x - ( - 50 ) } { 250 - ( - 50 ) }$$

Solve for x

$$x=-20$$

Steps for Solving Linear Equation

Subtract 32 from 50 to get 18.

$$\frac{18}{212-32}=\frac{x-\left(-50\right)}{250-\left(-50\right)}$$

Subtract 32 from 212 to get 180.

$$\frac{18}{180}=\frac{x-\left(-50\right)}{250-\left(-50\right)}$$

Reduce the fraction \frac{18}{180} to lowest terms by extracting and canceling out 18.

$$\frac{1}{10}=\frac{x-\left(-50\right)}{250-\left(-50\right)}$$

The opposite of -50 is 50.

$$\frac{1}{10}=\frac{x+50}{250-\left(-50\right)}$$

The opposite of -50 is 50.

$$\frac{1}{10}=\frac{x+50}{250+50}$$

Add 250 and 50 to get 300.

$$\frac{1}{10}=\frac{x+50}{300}$$

Divide each term of x+50 by 300 to get \frac{1}{300}x+\frac{1}{6}.

$$\frac{1}{10}=\frac{1}{300}x+\frac{1}{6}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{300}x+\frac{1}{6}=\frac{1}{10}$$

Subtract \frac{1}{6} from both sides.

$$\frac{1}{300}x=\frac{1}{10}-\frac{1}{6}$$

Least common multiple of 10 and 6 is 30. Convert \frac{1}{10} and \frac{1}{6} to fractions with denominator 30.

$$\frac{1}{300}x=\frac{3}{30}-\frac{5}{30}$$

Since \frac{3}{30} and \frac{5}{30} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{300}x=\frac{3-5}{30}$$

Subtract 5 from 3 to get -2.

$$\frac{1}{300}x=\frac{-2}{30}$$

Reduce the fraction \frac{-2}{30} to lowest terms by extracting and canceling out 2.

$$\frac{1}{300}x=-\frac{1}{15}$$

Multiply both sides by 300, the reciprocal of \frac{1}{300}.

$$x=-\frac{1}{15}\times 300$$

Express -\frac{1}{15}\times 300 as a single fraction.

$$x=\frac{-300}{15}$$

Divide -300 by 15 to get -20.

$$x=-20$$