Solve 50*(8*6-20*16)^2/28*22*24*26approx

$$\frac { 50 \times ( 8 \times 6 - 20 \times 16 ) ^ { 2 } } { 28 \times 22 \times 24 \times 26 } \approx$$

Evaluate

$$\frac{28900}{3003}\approx 9.623709624$$

Solution Steps

Cancel out 2 in both numerator and denominator.

$$\frac{25\left(6\times 8-16\times 20\right)^{2}}{14\times 22\times 24\times 26}$$

Multiply 6 and 8 to get 48.

$$\frac{25\left(48-16\times 20\right)^{2}}{14\times 22\times 24\times 26}$$

Multiply 16 and 20 to get 320.

$$\frac{25\left(48-320\right)^{2}}{14\times 22\times 24\times 26}$$

Subtract 320 from 48 to get -272.

$$\frac{25\left(-272\right)^{2}}{14\times 22\times 24\times 26}$$

Calculate -272 to the power of 2 and get 73984.

$$\frac{25\times 73984}{14\times 22\times 24\times 26}$$

Multiply 25 and 73984 to get 1849600.

$$\frac{1849600}{14\times 22\times 24\times 26}$$

Multiply 14 and 22 to get 308.

$$\frac{1849600}{308\times 24\times 26}$$

Multiply 308 and 24 to get 7392.

$$\frac{1849600}{7392\times 26}$$

Multiply 7392 and 26 to get 192192.

$$\frac{1849600}{192192}$$

Reduce the fraction \frac{1849600}{192192} to lowest terms by extracting and canceling out 64.

$$\frac{28900}{3003}$$

Factor

$$\frac{2 ^ {2} \cdot 5 ^ {2} \cdot 17 ^ {2}}{3 \cdot 7 \cdot 11 \cdot 13} = 9\frac{1873}{3003} = 9.623709623709624$$