Solve 5y+3/x=6

$$\frac { 5 y + 3 } { x } = 6$$

Solve for x

$$x=\frac{5y}{6}+\frac{1}{2}$$

$$y\neq -\frac{3}{5}$$

Steps for Solving Linear Equation

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.

$$5y+3=6x$$

Swap sides so that all variable terms are on the left hand side.

$$6x=5y+3$$

Divide both sides by 6.

$$\frac{6x}{6}=\frac{5y+3}{6}$$

Dividing by 6 undoes the multiplication by 6.

$$x=\frac{5y+3}{6}$$

Divide 5y+3 by 6.

$$x=\frac{5y}{6}+\frac{1}{2}$$

Variable x cannot be equal to 0.

$$x=\frac{5y}{6}+\frac{1}{2}\text{, }x\neq 0$$

Solve for y

$$y=\frac{6x-3}{5}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by x.

$$5y+3=6x$$

Subtract 3 from both sides.

$$5y=6x-3$$

Divide both sides by 5.

$$\frac{5y}{5}=\frac{6x-3}{5}$$

Dividing by 5 undoes the multiplication by 5.

$$y=\frac{6x-3}{5}$$