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\frac{5x-y}{12x+3y}+\frac{2y\left(4x+y\right)}{3\left(4x+y\right)^{2}}-\frac{y+x}{3y+12}
Factor the expressions that are not already factored in \frac{8xy+2y^{2}}{48x^{2}+24xy+3y^{2}}.
\frac{5x-y}{12x+3y}+\frac{2y}{3\left(4x+y\right)}-\frac{y+x}{3y+12}
Cancel out 4x+y in both numerator and denominator.
\frac{5x-y}{3\left(4x+y\right)}+\frac{2y}{3\left(4x+y\right)}-\frac{y+x}{3y+12}
Factor 12x+3y.
\frac{5x-y+2y}{3\left(4x+y\right)}-\frac{y+x}{3y+12}
Since \frac{5x-y}{3\left(4x+y\right)} and \frac{2y}{3\left(4x+y\right)} have the same denominator, add them by adding their numerators.
\frac{5x+y}{3\left(4x+y\right)}-\frac{y+x}{3y+12}
Combine like terms in 5x-y+2y.
\frac{5x+y}{3\left(4x+y\right)}-\frac{y+x}{3\left(y+4\right)}
Factor 3y+12.
\frac{\left(5x+y\right)\left(y+4\right)}{3\left(y+4\right)\left(4x+y\right)}-\frac{\left(y+x\right)\left(4x+y\right)}{3\left(y+4\right)\left(4x+y\right)}
To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 3\left(4x+y\right) and 3\left(y+4\right) is 3\left(y+4\right)\left(4x+y\right). Multiply \frac{5x+y}{3\left(4x+y\right)} times \frac{y+4}{y+4}. Multiply \frac{y+x}{3\left(y+4\right)} times \frac{4x+y}{4x+y}.
\frac{\left(5x+y\right)\left(y+4\right)-\left(y+x\right)\left(4x+y\right)}{3\left(y+4\right)\left(4x+y\right)}
Since \frac{\left(5x+y\right)\left(y+4\right)}{3\left(y+4\right)\left(4x+y\right)} and \frac{\left(y+x\right)\left(4x+y\right)}{3\left(y+4\right)\left(4x+y\right)} have the same denominator, subtract them by subtracting their numerators.
\frac{5xy+20x+y^{2}+4y-4yx-y^{2}-4x^{2}-xy}{3\left(y+4\right)\left(4x+y\right)}
Do the multiplications in \left(5x+y\right)\left(y+4\right)-\left(y+x\right)\left(4x+y\right).
\frac{20x+4y-4x^{2}}{3\left(y+4\right)\left(4x+y\right)}
Combine like terms in 5xy+20x+y^{2}+4y-4yx-y^{2}-4x^{2}-xy.
\frac{20x+4y-4x^{2}}{12xy+48x+3y^{2}+12y}
Expand 3\left(y+4\right)\left(4x+y\right).
\frac{5x-y}{12x+3y}+\frac{2y\left(4x+y\right)}{3\left(4x+y\right)^{2}}-\frac{y+x}{3y+12}
Factor the expressions that are not already factored in \frac{8xy+2y^{2}}{48x^{2}+24xy+3y^{2}}.
\frac{5x-y}{12x+3y}+\frac{2y}{3\left(4x+y\right)}-\frac{y+x}{3y+12}
Cancel out 4x+y in both numerator and denominator.
\frac{5x-y}{3\left(4x+y\right)}+\frac{2y}{3\left(4x+y\right)}-\frac{y+x}{3y+12}
Factor 12x+3y.
\frac{5x-y+2y}{3\left(4x+y\right)}-\frac{y+x}{3y+12}
Since \frac{5x-y}{3\left(4x+y\right)} and \frac{2y}{3\left(4x+y\right)} have the same denominator, add them by adding their numerators.
\frac{5x+y}{3\left(4x+y\right)}-\frac{y+x}{3y+12}
Combine like terms in 5x-y+2y.
\frac{5x+y}{3\left(4x+y\right)}-\frac{y+x}{3\left(y+4\right)}
Factor 3y+12.
\frac{\left(5x+y\right)\left(y+4\right)}{3\left(y+4\right)\left(4x+y\right)}-\frac{\left(y+x\right)\left(4x+y\right)}{3\left(y+4\right)\left(4x+y\right)}
To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 3\left(4x+y\right) and 3\left(y+4\right) is 3\left(y+4\right)\left(4x+y\right). Multiply \frac{5x+y}{3\left(4x+y\right)} times \frac{y+4}{y+4}. Multiply \frac{y+x}{3\left(y+4\right)} times \frac{4x+y}{4x+y}.
\frac{\left(5x+y\right)\left(y+4\right)-\left(y+x\right)\left(4x+y\right)}{3\left(y+4\right)\left(4x+y\right)}
Since \frac{\left(5x+y\right)\left(y+4\right)}{3\left(y+4\right)\left(4x+y\right)} and \frac{\left(y+x\right)\left(4x+y\right)}{3\left(y+4\right)\left(4x+y\right)} have the same denominator, subtract them by subtracting their numerators.
\frac{5xy+20x+y^{2}+4y-4yx-y^{2}-4x^{2}-xy}{3\left(y+4\right)\left(4x+y\right)}
Do the multiplications in \left(5x+y\right)\left(y+4\right)-\left(y+x\right)\left(4x+y\right).
\frac{20x+4y-4x^{2}}{3\left(y+4\right)\left(4x+y\right)}
Combine like terms in 5xy+20x+y^{2}+4y-4yx-y^{2}-4x^{2}-xy.
\frac{20x+4y-4x^{2}}{12xy+48x+3y^{2}+12y}
Expand 3\left(y+4\right)\left(4x+y\right).