Solve 5x/x^2-5x

$$\frac { 5 x } { x ^ { 2 } - 5 x }$$

Evaluate

$$\frac{5}{x-5}$$

Short Solution Steps

Factor the expressions that are not already factored.

$$\frac{5x}{x\left(x-5\right)}$$

Cancel out x in both numerator and denominator.

$$\frac{5}{x-5}$$

Differentiate w.r.t. x

$$-\frac{5}{\left(x-5\right)^{2}}$$

Steps Using Derivative Rule for Quotient

For any two differentiable functions, the derivative of the quotient of two functions is the denominator times the derivative of the numerator minus the numerator times the derivative of the denominator, all divided by the denominator squared.

$$\frac{\left(x^{2}-5x^{1}\right)\frac{\mathrm{d}}{\mathrm{d}x}(5x^{1})-5x^{1}\frac{\mathrm{d}}{\mathrm{d}x}(x^{2}-5x^{1})}{\left(x^{2}-5x^{1}\right)^{2}}$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$\frac{\left(x^{2}-5x^{1}\right)\times 5x^{1-1}-5x^{1}\left(2x^{2-1}-5x^{1-1}\right)}{\left(x^{2}-5x^{1}\right)^{2}}$$

Simplify.

$$\frac{\left(x^{2}-5x^{1}\right)\times 5x^{0}-5x^{1}\left(2x^{1}-5x^{0}\right)}{\left(x^{2}-5x^{1}\right)^{2}}$$

Multiply x^{2}-5x^{1} times 5x^{0}.

$$\frac{x^{2}\times 5x^{0}-5x^{1}\times 5x^{0}-5x^{1}\left(2x^{1}-5x^{0}\right)}{\left(x^{2}-5x^{1}\right)^{2}}$$

Multiply 5x^{1} times 2x^{1}-5x^{0}.

$$\frac{x^{2}\times 5x^{0}-5x^{1}\times 5x^{0}-\left(5x^{1}\times 2x^{1}+5x^{1}\left(-5\right)x^{0}\right)}{\left(x^{2}-5x^{1}\right)^{2}}$$

To multiply powers of the same base, add their exponents.

$$\frac{5x^{2}-5\times 5x^{1}-\left(5\times 2x^{1+1}+5\left(-5\right)x^{1}\right)}{\left(x^{2}-5x^{1}\right)^{2}}$$

Simplify.

$$\frac{5x^{2}-25x^{1}-\left(10x^{2}-25x^{1}\right)}{\left(x^{2}-5x^{1}\right)^{2}}$$

Combine like terms.

$$\frac{-5x^{2}}{\left(x^{2}-5x^{1}\right)^{2}}$$

For any term t, t^{1}=t.

$$\frac{-5x^{2}}{\left(x^{2}-5x\right)^{2}}$$