Solve for x
x\geq 1
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5x+7\leq 8x+4
Multiply both sides of the equation by 2. Since 2 is positive, the inequality direction remains the same.
5x+7-8x\leq 4
Subtract 8x from both sides.
-3x+7\leq 4
Combine 5x and -8x to get -3x.
-3x\leq 4-7
Subtract 7 from both sides.
-3x\leq -3
Subtract 7 from 4 to get -3.
x\geq \frac{-3}{-3}
Divide both sides by -3. Since -3 is negative, the inequality direction is changed.
x\geq 1
Divide -3 by -3 to get 1.
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