Solve frac{5c^{2}d^4}{6ab^3}*9a^2b^2/15cd=

$$\frac { 5 c ^ { 2 } d ^ { 4 } } { 6 a b ^ { 3 } } \cdot \frac { 9 a ^ { 2 } b ^ { 2 } } { 15 c d } =$$

Evaluate

$$\frac{acd^{3}}{2b}$$

Solution Steps

Cancel out 3 in both numerator and denominator.

$$\frac{5c^{2}d^{4}}{6ab^{3}}\times \frac{3a^{2}b^{2}}{5cd}$$

Multiply \frac{5c^{2}d^{4}}{6ab^{3}} times \frac{3a^{2}b^{2}}{5cd} by multiplying numerator times numerator and denominator times denominator.

$$\frac{5c^{2}d^{4}\times 3a^{2}b^{2}}{6ab^{3}\times 5cd}$$

Cancel out 3\times 5acdb^{2} in both numerator and denominator.

$$\frac{acd^{3}}{2b}$$

Differentiate w.r.t. b

$$-\frac{acd^{3}}{2b^{2}}$$