Solve 5b^2/c=k(b)

$$\frac { 5 b ^ { 2 } } { c } = k ( b )$$

Solve for c

$$\left\{\begin{matrix}c=\frac{5b}{k}\text{, }&b\neq 0\text{ and }k\neq 0\\c\neq 0\text{, }&b=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Variable c cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by c.

$$5b^{2}=kbc$$

Swap sides so that all variable terms are on the left hand side.

$$kbc=5b^{2}$$

The equation is in standard form.

$$bkc=5b^{2}$$

Divide both sides by kb.

$$\frac{bkc}{bk}=\frac{5b^{2}}{bk}$$

Dividing by kb undoes the multiplication by kb.

$$c=\frac{5b^{2}}{bk}$$

Divide 5b^{2} by kb.

$$c=\frac{5b}{k}$$

Variable c cannot be equal to 0.

$$c=\frac{5b}{k}\text{, }c\neq 0$$

Solve for b

$$b=\frac{ck}{5}$$

$$b=0\text{, }c\neq 0$$