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Solve for a (complex solution)
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2\left(5a-1\right)-3\left(3a-1\right)=1\left(a+1\right)
Multiply both sides of the equation by 12, the least common multiple of 6,4,12.
10a-2-3\left(3a-1\right)=1\left(a+1\right)
Use the distributive property to multiply 2 by 5a-1.
10a-2-9a+3=1\left(a+1\right)
Use the distributive property to multiply -3 by 3a-1.
a-2+3=1\left(a+1\right)
Combine 10a and -9a to get a.
a+1=1\left(a+1\right)
Add -2 and 3 to get 1.
a+1=a+1
Use the distributive property to multiply 1 by a+1.
a+1-a=1
Subtract a from both sides.
1=1
Combine a and -a to get 0.
\text{true}
Compare 1 and 1.
a\in \mathrm{C}
This is true for any a.
2\left(5a-1\right)-3\left(3a-1\right)=1\left(a+1\right)
Multiply both sides of the equation by 12, the least common multiple of 6,4,12.
10a-2-3\left(3a-1\right)=1\left(a+1\right)
Use the distributive property to multiply 2 by 5a-1.
10a-2-9a+3=1\left(a+1\right)
Use the distributive property to multiply -3 by 3a-1.
a-2+3=1\left(a+1\right)
Combine 10a and -9a to get a.
a+1=1\left(a+1\right)
Add -2 and 3 to get 1.
a+1=a+1
Use the distributive property to multiply 1 by a+1.
a+1-a=1
Subtract a from both sides.
1=1
Combine a and -a to get 0.
\text{true}
Compare 1 and 1.
a\in \mathrm{R}
This is true for any a.