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\frac{\left(5-3i\right)\left(10+4i\right)}{\left(10-4i\right)\left(10+4i\right)}
Multiply both numerator and denominator by the complex conjugate of the denominator, 10+4i.
\frac{\left(5-3i\right)\left(10+4i\right)}{10^{2}-4^{2}i^{2}}
Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\left(5-3i\right)\left(10+4i\right)}{116}
By definition, i^{2} is -1. Calculate the denominator.
\frac{5\times 10+5\times \left(4i\right)-3i\times 10-3\times 4i^{2}}{116}
Multiply complex numbers 5-3i and 10+4i like you multiply binomials.
\frac{5\times 10+5\times \left(4i\right)-3i\times 10-3\times 4\left(-1\right)}{116}
By definition, i^{2} is -1.
\frac{50+20i-30i+12}{116}
Do the multiplications in 5\times 10+5\times \left(4i\right)-3i\times 10-3\times 4\left(-1\right).
\frac{50+12+\left(20-30\right)i}{116}
Combine the real and imaginary parts in 50+20i-30i+12.
\frac{62-10i}{116}
Do the additions in 50+12+\left(20-30\right)i.
\frac{31}{58}-\frac{5}{58}i
Divide 62-10i by 116 to get \frac{31}{58}-\frac{5}{58}i.
Re(\frac{\left(5-3i\right)\left(10+4i\right)}{\left(10-4i\right)\left(10+4i\right)})
Multiply both numerator and denominator of \frac{5-3i}{10-4i} by the complex conjugate of the denominator, 10+4i.
Re(\frac{\left(5-3i\right)\left(10+4i\right)}{10^{2}-4^{2}i^{2}})
Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
Re(\frac{\left(5-3i\right)\left(10+4i\right)}{116})
By definition, i^{2} is -1. Calculate the denominator.
Re(\frac{5\times 10+5\times \left(4i\right)-3i\times 10-3\times 4i^{2}}{116})
Multiply complex numbers 5-3i and 10+4i like you multiply binomials.
Re(\frac{5\times 10+5\times \left(4i\right)-3i\times 10-3\times 4\left(-1\right)}{116})
By definition, i^{2} is -1.
Re(\frac{50+20i-30i+12}{116})
Do the multiplications in 5\times 10+5\times \left(4i\right)-3i\times 10-3\times 4\left(-1\right).
Re(\frac{50+12+\left(20-30\right)i}{116})
Combine the real and imaginary parts in 50+20i-30i+12.
Re(\frac{62-10i}{116})
Do the additions in 50+12+\left(20-30\right)i.
Re(\frac{31}{58}-\frac{5}{58}i)
Divide 62-10i by 116 to get \frac{31}{58}-\frac{5}{58}i.
\frac{31}{58}
The real part of \frac{31}{58}-\frac{5}{58}i is \frac{31}{58}.