Solve 5(2h)-5(h(h+2))/h(h+2)(2h)

$$\frac { 5 ( 2 h ) - 5 ( h ( h + 2 ) ) } { h ( h + 2 ) ( 2 h ) }$$

Evaluate

$$-\frac{5}{2\left(h+2\right)}$$

Short Solution Steps

Multiply h and h to get h^{2}.

$$\frac{5\times 2h-5h\left(h+2\right)}{h^{2}\left(h+2\right)\times 2}$$

Multiply 5 and 2 to get 10.

$$\frac{10h-5h\left(h+2\right)}{h^{2}\left(h+2\right)\times 2}$$

Factor the expressions that are not already factored.

$$\frac{-5h^{2}}{2\left(h+2\right)h^{2}}$$

Cancel out h^{2} in both numerator and denominator.

$$\frac{-5}{2\left(h+2\right)}$$

Expand the expression.

$$\frac{-5}{2h+4}$$

Expand

$$-\frac{5}{2\left(h+2\right)}$$

Short Solution Steps

Multiply h and h to get h^{2}.

$$\frac{5\times 2h-5h\left(h+2\right)}{h^{2}\left(h+2\right)\times 2}$$

Multiply 5 and 2 to get 10.

$$\frac{10h-5h\left(h+2\right)}{h^{2}\left(h+2\right)\times 2}$$

Factor the expressions that are not already factored.

$$\frac{-5h^{2}}{2\left(h+2\right)h^{2}}$$

Cancel out h^{2} in both numerator and denominator.

$$\frac{-5}{2\left(h+2\right)}$$

Expand the expression.

$$\frac{-5}{2h+4}$$