Skip to main content
Solve for x
Tick mark Image
Graph

Similar Problems from Web Search

Share

\left(x+2\right)\times 5-\left(x-3\right)\times 6=\left(x-3\right)\left(x+2\right)
Variable x cannot be equal to any of the values -2,3 since division by zero is not defined. Multiply both sides of the equation by \left(x-3\right)\left(x+2\right), the least common multiple of x-3,x+2.
5x+10-\left(x-3\right)\times 6=\left(x-3\right)\left(x+2\right)
Use the distributive property to multiply x+2 by 5.
5x+10-\left(6x-18\right)=\left(x-3\right)\left(x+2\right)
Use the distributive property to multiply x-3 by 6.
5x+10-6x+18=\left(x-3\right)\left(x+2\right)
To find the opposite of 6x-18, find the opposite of each term.
-x+10+18=\left(x-3\right)\left(x+2\right)
Combine 5x and -6x to get -x.
-x+28=\left(x-3\right)\left(x+2\right)
Add 10 and 18 to get 28.
-x+28=x^{2}-x-6
Use the distributive property to multiply x-3 by x+2 and combine like terms.
-x+28-x^{2}=-x-6
Subtract x^{2} from both sides.
-x+28-x^{2}+x=-6
Add x to both sides.
28-x^{2}=-6
Combine -x and x to get 0.
-x^{2}=-6-28
Subtract 28 from both sides.
-x^{2}=-34
Subtract 28 from -6 to get -34.
x^{2}=\frac{-34}{-1}
Divide both sides by -1.
x^{2}=34
Fraction \frac{-34}{-1} can be simplified to 34 by removing the negative sign from both the numerator and the denominator.
x=\sqrt{34} x=-\sqrt{34}
Take the square root of both sides of the equation.
\left(x+2\right)\times 5-\left(x-3\right)\times 6=\left(x-3\right)\left(x+2\right)
Variable x cannot be equal to any of the values -2,3 since division by zero is not defined. Multiply both sides of the equation by \left(x-3\right)\left(x+2\right), the least common multiple of x-3,x+2.
5x+10-\left(x-3\right)\times 6=\left(x-3\right)\left(x+2\right)
Use the distributive property to multiply x+2 by 5.
5x+10-\left(6x-18\right)=\left(x-3\right)\left(x+2\right)
Use the distributive property to multiply x-3 by 6.
5x+10-6x+18=\left(x-3\right)\left(x+2\right)
To find the opposite of 6x-18, find the opposite of each term.
-x+10+18=\left(x-3\right)\left(x+2\right)
Combine 5x and -6x to get -x.
-x+28=\left(x-3\right)\left(x+2\right)
Add 10 and 18 to get 28.
-x+28=x^{2}-x-6
Use the distributive property to multiply x-3 by x+2 and combine like terms.
-x+28-x^{2}=-x-6
Subtract x^{2} from both sides.
-x+28-x^{2}+x=-6
Add x to both sides.
28-x^{2}=-6
Combine -x and x to get 0.
28-x^{2}+6=0
Add 6 to both sides.
34-x^{2}=0
Add 28 and 6 to get 34.
-x^{2}+34=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\left(-1\right)\times 34}}{2\left(-1\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -1 for a, 0 for b, and 34 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-1\right)\times 34}}{2\left(-1\right)}
Square 0.
x=\frac{0±\sqrt{4\times 34}}{2\left(-1\right)}
Multiply -4 times -1.
x=\frac{0±\sqrt{136}}{2\left(-1\right)}
Multiply 4 times 34.
x=\frac{0±2\sqrt{34}}{2\left(-1\right)}
Take the square root of 136.
x=\frac{0±2\sqrt{34}}{-2}
Multiply 2 times -1.
x=-\sqrt{34}
Now solve the equation x=\frac{0±2\sqrt{34}}{-2} when ± is plus.
x=\sqrt{34}
Now solve the equation x=\frac{0±2\sqrt{34}}{-2} when ± is minus.
x=-\sqrt{34} x=\sqrt{34}
The equation is now solved.