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5+\left(x-4\right)\left(-2\right)=\left(x-3\right)\left(-5\right)
Variable x cannot be equal to any of the values 3,4 since division by zero is not defined. Multiply both sides of the equation by \left(x-4\right)\left(x-3\right), the least common multiple of x^{2}-7x+12,x-3,x-4.
5-2x+8=\left(x-3\right)\left(-5\right)
Use the distributive property to multiply x-4 by -2.
13-2x=\left(x-3\right)\left(-5\right)
Add 5 and 8 to get 13.
13-2x=-5x+15
Use the distributive property to multiply x-3 by -5.
13-2x+5x=15
Add 5x to both sides.
13+3x=15
Combine -2x and 5x to get 3x.
3x=15-13
Subtract 13 from both sides.
3x=2
Subtract 13 from 15 to get 2.
x=\frac{2}{3}
Divide both sides by 3.