Solve 5/x^2-4x+3+1/2x-6=1/2x^2-8x+6

$$\frac { 5 } { x ^ { 2 } - 4 x + 3 } + \frac { 1 } { 2 x - 6 } = \frac { 1 } { 2 x ^ { 2 } - 8 x + 6 }$$

Solve for x

$$x=-8$$

Steps for Solving Linear Equation

Variable x cannot be equal to any of the values 1,3 since division by zero is not defined. Multiply both sides of the equation by 2\left(x-3\right)\left(x-1\right), the least common multiple of x^{2}-4x+3,2x-6,2x^{2}-8x+6.

$$2\times 5+x-1=1$$

Multiply 2 and 5 to get 10.

$$10+x-1=1$$

Subtract 1 from 10 to get 9.

$$9+x=1$$

Subtract 9 from both sides.

$$x=1-9$$

Subtract 9 from 1 to get -8.

$$x=-8$$