Solve 5/a=4/bquad[b]

$$\frac { 5 } { a } = \frac { 4 } { b } \quad [ b ]$$

Solve for a

$$a = \frac{5}{4} = 1\frac{1}{4} = 1.25$$

$$b\neq 0$$

Steps for Solving Linear Equation

Variable a cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by ab, the least common multiple of a,b.

$$b\times 5=a\times 4b$$

Swap sides so that all variable terms are on the left hand side.

$$a\times 4b=b\times 5$$

The equation is in standard form.

$$4ba=5b$$

Divide both sides by 4b.

$$\frac{4ba}{4b}=\frac{5b}{4b}$$

Dividing by 4b undoes the multiplication by 4b.

$$a=\frac{5b}{4b}$$

Divide 5b by 4b.

$$a=\frac{5}{4}$$

Solve for b

$$b\neq 0$$

$$a = \frac{5}{4} = 1\frac{1}{4} = 1.25$$

Steps for Solving Linear Equation

Variable b cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by ab, the least common multiple of a,b.

$$b\times 5=a\times 4b$$

Subtract a\times 4b from both sides.

$$b\times 5-a\times 4b=0$$

Multiply -1 and 4 to get -4.

$$b\times 5-4ab=0$$

Combine all terms containing b.

$$\left(5-4a\right)b=0$$

Divide 0 by 5-4a.

$$b=0$$

Variable b cannot be equal to 0.

$$b\in \emptyset$$