Solve 5/9(F-32)=C

$$\frac { 5 } { 9 } ( F - 32 ) = C$$

Solve for C

$$C=\frac{5\left(F-32\right)}{9}$$

Solution Steps

Use the distributive property to multiply \frac{5}{9} by F-32.

$$\frac{5}{9}F-\frac{160}{9}=C$$

Swap sides so that all variable terms are on the left hand side.

$$C=\frac{5}{9}F-\frac{160}{9}$$

Solve for F

$$F=\frac{9C}{5}+32$$

Steps for Solving Linear Equation

Use the distributive property to multiply \frac{5}{9} by F-32.

$$\frac{5}{9}F-\frac{160}{9}=C$$

Add \frac{160}{9} to both sides.

$$\frac{5}{9}F=C+\frac{160}{9}$$

Divide both sides of the equation by \frac{5}{9}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{5}{9}F}{\frac{5}{9}}=\frac{C+\frac{160}{9}}{\frac{5}{9}}$$

Dividing by \frac{5}{9} undoes the multiplication by \frac{5}{9}.

$$F=\frac{C+\frac{160}{9}}{\frac{5}{9}}$$

Divide C+\frac{160}{9} by \frac{5}{9} by multiplying C+\frac{160}{9} by the reciprocal of \frac{5}{9}.

$$F=\frac{9C}{5}+32$$