Solve 5/7x>x+4

$$\frac { 5 } { 7 } x > x + 4$$

Solve for x

$$x<-14$$

Solution Steps

Subtract x from both sides.

$$\frac{5}{7}x-x>4$$

Combine \frac{5}{7}x and -x to get -\frac{2}{7}x.

$$-\frac{2}{7}x>4$$

Multiply both sides by -\frac{7}{2}, the reciprocal of -\frac{2}{7}. Since -\frac{2}{7} is negative, the inequality direction is changed.

$$x<4\left(-\frac{7}{2}\right)$$

Express 4\left(-\frac{7}{2}\right) as a single fraction.

$$x<\frac{4\left(-7\right)}{2}$$

Multiply 4 and -7 to get -28.

$$x<\frac{-28}{2}$$

Divide -28 by 2 to get -14.

$$x<-14$$