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\frac{5}{6}y+1+\frac{1}{3}y=\frac{5}{9}
Add \frac{1}{3}y to both sides.
\frac{7}{6}y+1=\frac{5}{9}
Combine \frac{5}{6}y and \frac{1}{3}y to get \frac{7}{6}y.
\frac{7}{6}y=\frac{5}{9}-1
Subtract 1 from both sides.
\frac{7}{6}y=\frac{5}{9}-\frac{9}{9}
Convert 1 to fraction \frac{9}{9}.
\frac{7}{6}y=\frac{5-9}{9}
Since \frac{5}{9} and \frac{9}{9} have the same denominator, subtract them by subtracting their numerators.
\frac{7}{6}y=-\frac{4}{9}
Subtract 9 from 5 to get -4.
y=-\frac{4}{9}\times \frac{6}{7}
Multiply both sides by \frac{6}{7}, the reciprocal of \frac{7}{6}.
y=\frac{-4\times 6}{9\times 7}
Multiply -\frac{4}{9} times \frac{6}{7} by multiplying numerator times numerator and denominator times denominator.
y=\frac{-24}{63}
Do the multiplications in the fraction \frac{-4\times 6}{9\times 7}.
y=-\frac{8}{21}
Reduce the fraction \frac{-24}{63} to lowest terms by extracting and canceling out 3.