Solve 5/6(B-C)=A

$$\frac { 5 } { 6 } ( B - C ) = A$$

Solve for A

$$A=\frac{5\left(B-C\right)}{6}$$

Solution Steps

Use the distributive property to multiply \frac{5}{6} by B-C.

$$\frac{5}{6}B-\frac{5}{6}C=A$$

Swap sides so that all variable terms are on the left hand side.

$$A=\frac{5}{6}B-\frac{5}{6}C$$

Solve for B

$$B=\frac{6A}{5}+C$$

Steps for Solving Linear Equation

Use the distributive property to multiply \frac{5}{6} by B-C.

$$\frac{5}{6}B-\frac{5}{6}C=A$$

Add \frac{5}{6}C to both sides.

$$\frac{5}{6}B=A+\frac{5}{6}C$$

The equation is in standard form.

$$\frac{5}{6}B=\frac{5C}{6}+A$$

Divide both sides of the equation by \frac{5}{6}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{5}{6}B}{\frac{5}{6}}=\frac{\frac{5C}{6}+A}{\frac{5}{6}}$$

Dividing by \frac{5}{6} undoes the multiplication by \frac{5}{6}.

$$B=\frac{\frac{5C}{6}+A}{\frac{5}{6}}$$

Divide A+\frac{5C}{6} by \frac{5}{6} by multiplying A+\frac{5C}{6} by the reciprocal of \frac{5}{6}.

$$B=\frac{6A}{5}+C$$