Solve 5/6*4/15-3/5*20/18

$$\frac { 5 } { 6 } \times \frac { 4 } { 15 } - \frac { 3 } { 5 } \times \frac { 20 } { 18 }$$

Evaluate

$$-\frac{4}{9}\approx -0.444444444$$

Solution Steps

Multiply \frac{5}{6} times \frac{4}{15} by multiplying numerator times numerator and denominator times denominator.

$$\frac{5\times 4}{6\times 15}-\frac{3}{5}\times \frac{20}{18}$$

Do the multiplications in the fraction \frac{5\times 4}{6\times 15}.

$$\frac{20}{90}-\frac{3}{5}\times \frac{20}{18}$$

Reduce the fraction \frac{20}{90} to lowest terms by extracting and canceling out 10.

$$\frac{2}{9}-\frac{3}{5}\times \frac{20}{18}$$

Reduce the fraction \frac{20}{18} to lowest terms by extracting and canceling out 2.

$$\frac{2}{9}-\frac{3}{5}\times \frac{10}{9}$$

Multiply \frac{3}{5} times \frac{10}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{2}{9}-\frac{3\times 10}{5\times 9}$$

Do the multiplications in the fraction \frac{3\times 10}{5\times 9}.

$$\frac{2}{9}-\frac{30}{45}$$

Reduce the fraction \frac{30}{45} to lowest terms by extracting and canceling out 15.

$$\frac{2}{9}-\frac{2}{3}$$

Least common multiple of 9 and 3 is 9. Convert \frac{2}{9} and \frac{2}{3} to fractions with denominator 9.

$$\frac{2}{9}-\frac{6}{9}$$

Since \frac{2}{9} and \frac{6}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2-6}{9}$$

Subtract 6 from 2 to get -4.

$$-\frac{4}{9}$$

Factor

$$-\frac{4}{9} = -0.4444444444444444$$