Solve 5/6*(1/2-1)^3+sqrt[3]{1/4*(-2)}+0,6=

$$\frac { 5 } { 6 } \cdot ( \frac { 1 } { 2 } - 1 ) ^ { 3 } + \sqrt[ 3 ] { \frac { 1 } { 4 } \cdot ( - 2 ) } + 0,6 =$$

Evaluate

$$-\frac{2^{\frac{2}{3}}}{2}+\frac{119}{240}\approx -0.297867193$$

Solution Steps

Subtract 1 from \frac{1}{2} to get -\frac{1}{2}.

$$\frac{5}{6}\left(-\frac{1}{2}\right)^{3}+\sqrt[3]{\frac{1}{4}\left(-2\right)}+0,6$$

Calculate -\frac{1}{2} to the power of 3 and get -\frac{1}{8}.

$$\frac{5}{6}\left(-\frac{1}{8}\right)+\sqrt[3]{\frac{1}{4}\left(-2\right)}+0,6$$

Multiply \frac{5}{6} and -\frac{1}{8} to get -\frac{5}{48}.

$$-\frac{5}{48}+\sqrt[3]{\frac{1}{4}\left(-2\right)}+0,6$$

Multiply \frac{1}{4} and -2 to get -\frac{1}{2}.

$$-\frac{5}{48}+\sqrt[3]{-\frac{1}{2}}+0,6$$

Add -\frac{5}{48} and 0,6 to get \frac{119}{240}.

$$\frac{119}{240}+\sqrt[3]{-\frac{1}{2}}$$

Factor

$$\frac{-\frac{240}{\sqrt[3]{2}} + 119}{240} = -0.29786719265076644$$