Solve 5/6+(2-123/35):9/25-12/7

$$\frac { 5 } { 6 } + ( 2 - 1 \frac { 23 } { 35 } ) : \frac { 9 } { 25 } - 1 \frac { 2 } { 7 }$$

Evaluate

$$\frac{1}{2}=0.5$$

Solution Steps

Multiply 1 and 35 to get 35.

$$\frac{5}{6}+\frac{2-\frac{35+23}{35}}{\frac{9}{25}}-\frac{1\times 7+2}{7}$$

Add 35 and 23 to get 58.

$$\frac{5}{6}+\frac{2-\frac{58}{35}}{\frac{9}{25}}-\frac{1\times 7+2}{7}$$

Convert 2 to fraction \frac{70}{35}.

$$\frac{5}{6}+\frac{\frac{70}{35}-\frac{58}{35}}{\frac{9}{25}}-\frac{1\times 7+2}{7}$$

Since \frac{70}{35} and \frac{58}{35} have the same denominator, subtract them by subtracting their numerators.

$$\frac{5}{6}+\frac{\frac{70-58}{35}}{\frac{9}{25}}-\frac{1\times 7+2}{7}$$

Subtract 58 from 70 to get 12.

$$\frac{5}{6}+\frac{\frac{12}{35}}{\frac{9}{25}}-\frac{1\times 7+2}{7}$$

Divide \frac{12}{35} by \frac{9}{25} by multiplying \frac{12}{35} by the reciprocal of \frac{9}{25}.

$$\frac{5}{6}+\frac{12}{35}\times \frac{25}{9}-\frac{1\times 7+2}{7}$$

Multiply \frac{12}{35} times \frac{25}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{5}{6}+\frac{12\times 25}{35\times 9}-\frac{1\times 7+2}{7}$$

Do the multiplications in the fraction \frac{12\times 25}{35\times 9}.

$$\frac{5}{6}+\frac{300}{315}-\frac{1\times 7+2}{7}$$

Reduce the fraction \frac{300}{315} to lowest terms by extracting and canceling out 15.

$$\frac{5}{6}+\frac{20}{21}-\frac{1\times 7+2}{7}$$

Least common multiple of 6 and 21 is 42. Convert \frac{5}{6} and \frac{20}{21} to fractions with denominator 42.

$$\frac{35}{42}+\frac{40}{42}-\frac{1\times 7+2}{7}$$

Since \frac{35}{42} and \frac{40}{42} have the same denominator, add them by adding their numerators.

$$\frac{35+40}{42}-\frac{1\times 7+2}{7}$$

Add 35 and 40 to get 75.

$$\frac{75}{42}-\frac{1\times 7+2}{7}$$

Reduce the fraction \frac{75}{42} to lowest terms by extracting and canceling out 3.

$$\frac{25}{14}-\frac{1\times 7+2}{7}$$

Multiply 1 and 7 to get 7.

$$\frac{25}{14}-\frac{7+2}{7}$$

Add 7 and 2 to get 9.

$$\frac{25}{14}-\frac{9}{7}$$

Least common multiple of 14 and 7 is 14. Convert \frac{25}{14} and \frac{9}{7} to fractions with denominator 14.

$$\frac{25}{14}-\frac{18}{14}$$

Since \frac{25}{14} and \frac{18}{14} have the same denominator, subtract them by subtracting their numerators.

$$\frac{25-18}{14}$$

Subtract 18 from 25 to get 7.

$$\frac{7}{14}$$

Reduce the fraction \frac{7}{14} to lowest terms by extracting and canceling out 7.

$$\frac{1}{2}$$

Factor

$$\frac{1}{2} = 0.5$$