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\frac{5}{6}+\frac{\left(1\times 4+3\right)\times 5}{4\left(2\times 5+2\right)}
Divide \frac{1\times 4+3}{4} by \frac{2\times 5+2}{5} by multiplying \frac{1\times 4+3}{4} by the reciprocal of \frac{2\times 5+2}{5}.
\frac{5}{6}+\frac{\left(4+3\right)\times 5}{4\left(2\times 5+2\right)}
Multiply 1 and 4 to get 4.
\frac{5}{6}+\frac{7\times 5}{4\left(2\times 5+2\right)}
Add 4 and 3 to get 7.
\frac{5}{6}+\frac{35}{4\left(2\times 5+2\right)}
Multiply 7 and 5 to get 35.
\frac{5}{6}+\frac{35}{4\left(10+2\right)}
Multiply 2 and 5 to get 10.
\frac{5}{6}+\frac{35}{4\times 12}
Add 10 and 2 to get 12.
\frac{5}{6}+\frac{35}{48}
Multiply 4 and 12 to get 48.
\frac{40}{48}+\frac{35}{48}
Least common multiple of 6 and 48 is 48. Convert \frac{5}{6} and \frac{35}{48} to fractions with denominator 48.
\frac{40+35}{48}
Since \frac{40}{48} and \frac{35}{48} have the same denominator, add them by adding their numerators.
\frac{75}{48}
Add 40 and 35 to get 75.
\frac{25}{16}
Reduce the fraction \frac{75}{48} to lowest terms by extracting and canceling out 3.