Solve 5/6+7/9*4/3-1/2

$$\frac { 5 } { 6 } + \frac { 7 } { 9 } \cdot \frac { 4 } { 3 } - \frac { 1 } { 2 }$$

Evaluate

$$\frac{37}{27}\approx 1.37037037$$

Solution Steps

Multiply \frac{7}{9} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{5}{6}+\frac{7\times 4}{9\times 3}-\frac{1}{2}$$

Do the multiplications in the fraction \frac{7\times 4}{9\times 3}.

$$\frac{5}{6}+\frac{28}{27}-\frac{1}{2}$$

Least common multiple of 6 and 27 is 54. Convert \frac{5}{6} and \frac{28}{27} to fractions with denominator 54.

$$\frac{45}{54}+\frac{56}{54}-\frac{1}{2}$$

Since \frac{45}{54} and \frac{56}{54} have the same denominator, add them by adding their numerators.

$$\frac{45+56}{54}-\frac{1}{2}$$

Add 45 and 56 to get 101.

$$\frac{101}{54}-\frac{1}{2}$$

Least common multiple of 54 and 2 is 54. Convert \frac{101}{54} and \frac{1}{2} to fractions with denominator 54.

$$\frac{101}{54}-\frac{27}{54}$$

Since \frac{101}{54} and \frac{27}{54} have the same denominator, subtract them by subtracting their numerators.

$$\frac{101-27}{54}$$

Subtract 27 from 101 to get 74.

$$\frac{74}{54}$$

Reduce the fraction \frac{74}{54} to lowest terms by extracting and canceling out 2.

$$\frac{37}{27}$$

Factor

$$\frac{37}{3 ^ {3}} = 1\frac{10}{27} = 1.3703703703703705$$