Solve 5/6+1/9*4/3-1/2=

$$\frac { 5 } { 6 } + \frac { 1 } { 9 } \cdot \frac { 4 } { 3 } - \frac { 1 } { 2 } =$$

Evaluate

$$\frac{13}{27}\approx 0.481481481$$

Solution Steps

Multiply \frac{1}{9} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{5}{6}+\frac{1\times 4}{9\times 3}-\frac{1}{2}$$

Do the multiplications in the fraction \frac{1\times 4}{9\times 3}.

$$\frac{5}{6}+\frac{4}{27}-\frac{1}{2}$$

Least common multiple of 6 and 27 is 54. Convert \frac{5}{6} and \frac{4}{27} to fractions with denominator 54.

$$\frac{45}{54}+\frac{8}{54}-\frac{1}{2}$$

Since \frac{45}{54} and \frac{8}{54} have the same denominator, add them by adding their numerators.

$$\frac{45+8}{54}-\frac{1}{2}$$

Add 45 and 8 to get 53.

$$\frac{53}{54}-\frac{1}{2}$$

Least common multiple of 54 and 2 is 54. Convert \frac{53}{54} and \frac{1}{2} to fractions with denominator 54.

$$\frac{53}{54}-\frac{27}{54}$$

Since \frac{53}{54} and \frac{27}{54} have the same denominator, subtract them by subtracting their numerators.

$$\frac{53-27}{54}$$

Subtract 27 from 53 to get 26.

$$\frac{26}{54}$$

Reduce the fraction \frac{26}{54} to lowest terms by extracting and canceling out 2.

$$\frac{13}{27}$$

Factor

$$\frac{13}{3 ^ {3}} = 0.48148148148148145$$